7c^2-19c-6=0

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Solution for 7c^2-19c-6=0 equation:


Simplifying
7c2 + -19c + -6 = 0

Reorder the terms:
-6 + -19c + 7c2 = 0

Solving
-6 + -19c + 7c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-2 + -7c)(3 + -1c) = 0

Subproblem 1

Set the factor '(-2 + -7c)' equal to zero and attempt to solve: Simplifying -2 + -7c = 0 Solving -2 + -7c = 0 Move all terms containing c to the left, all other terms to the right. Add '2' to each side of the equation. -2 + 2 + -7c = 0 + 2 Combine like terms: -2 + 2 = 0 0 + -7c = 0 + 2 -7c = 0 + 2 Combine like terms: 0 + 2 = 2 -7c = 2 Divide each side by '-7'. c = -0.2857142857 Simplifying c = -0.2857142857

Subproblem 2

Set the factor '(3 + -1c)' equal to zero and attempt to solve: Simplifying 3 + -1c = 0 Solving 3 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -1c = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -1c = 0 + -3 -1c = 0 + -3 Combine like terms: 0 + -3 = -3 -1c = -3 Divide each side by '-1'. c = 3 Simplifying c = 3

Solution

c = {-0.2857142857, 3}

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